If $$\frac{3\sqrt{3}\sec \theta + 4 \tan \theta}{3 \tan \theta + \sqrt{3} \sec \theta} = 2, 0^\circ < \theta < 90^\circ$$, then the value of $$\cos \theta$$ will be:

A

$$\frac{\sqrt{3}}{2}$$

B

$$\frac{1}{\sqrt{2}}$$

C

$$\frac{1}{4}$$

D

$$\frac{1}{2}$$