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$$1 + 2 \tan^2 \theta + 2 \sin \theta \sec^2 \theta, 0^\circ < \theta < 90^\circ$$, is equal to:
$$\frac{1 - \cos \theta}{1 + \cos \theta}$$
$$\frac{1 + \cos \theta}{1 - \cos \theta}$$
$$\frac{1 - \sin \theta}{1 + \sin \theta}$$
$$\frac{1 + \sin \theta}{1 - \sin \theta}$$
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