The value of $$\sin 18^{\circ}$$ is given as $$\frac{\sqrt{5}-1}{4}$$ Using this value, find the value of $$\cos 18^{\circ}$$.

A

$$\frac{\sqrt{10+2\sqrt{5}}}{4}$$

B

$$\frac{\sqrt{5}+1}{4}$$

C

$$\frac{\sqrt{6}+\sqrt{2}}{4}$$

D

$$\frac{\sqrt{10-2\sqrt{5}}}{4}$$