Question 53

The value of $$30\div6\times5$$ of $$(2+3)-12(3\times2)$$ is equal to:

Solution

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$$30\div6\times5$$ of $$(2+3)-12(3\times2)$$

Using BODMAS rule, we get

=$$30\div6\times5$$ of $$(2+3)-12(3\times2)$$

$$=5\times5\times5-12\times6$$

$$=125-72$$

$$=53$$

Option D is correct.

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