Question 53

The value of $$[0.08 \div 1.2 of (3.4 - 2.6) \times 0.8 of 3.2] of \frac{9}{16}$$ lies between:

Solution

=$$[0.08 \div 1.2 of (3.4 - 2.6) \times 0.8 of 3.2] of \frac{9}{16}$$
=$$[0.08 \div 1.2 of 0.8 \times 0.8 of 3.2] of \frac{9}{16}$$
=$$[0.08 \div 0.96 \times 2.56] \times \frac{9}{16}$$
=$$[(1/12) \times 2.56] \times \frac{9}{16}$$
=$$(16/75) \times \frac{9}{16}$$
=9/75
=0.12

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SSC GD 18th Feb 2019 Shift-3

The value of $$[0.08 \div 1.2 of (3.4 - 2.6) \times 0.8 of 3.2] of \frac{9}{16}$$ lies between:

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