The unbalanced equation for the reaction of $$\text{P}_4\text{S}_3$$ with nitrate in aqueous acidic medium is given below. $$\text{P}_4\text{S}_3 + \text{NO}_3^- \rightarrow \text{H}_3\text{PO}_4 + \text{SO}_4^{2-} + \text{NO}$$. The number of mol of water required per mol of $$\text{P}_4\text{S}_3$$ is

A

18

B

$$\frac{8}{3}$$

C

8

D

28