The sides AB and AC of $$\triangle$$ ABC are produced to points D and E. respectively. The bisectors of $$\angle$$ CBD and $$\angle$$ BCE meet at P. If $$\angle A = 88^{\circ}$$,then the measure of $$\angle$$ P is:

A

$$46^{\circ}$$

B

$$56^{\circ}$$

C

$$51^{\circ}$$

D

$$61^{\circ}$$