If $$3\sqrt{3}x^3 - 2\sqrt2 y^3 = (\sqrt3 x - \sqrt2 y)(Ax^2 + By^2 + Cxy)$$, then the value of $$(A \times B) \div C$$ is:

A

$$6\sqrt6$$

B

$$6\sqrt3$$

C

$$\sqrt3$$

D

$$\sqrt6$$