If $$3(\sec^2 \theta + \tan^2 \theta) = 5, 0^\circ < \theta < 90^\circ$$, then the value of $$\cosec \theta$$ is:

A

$$\frac{1}{\sqrt{3}}$$

B

$$\frac{2\sqrt{3}}{3}$$

C

2

D

$$\frac{1}{2}$$