Question 53

If 2cosAsinB = x, then the value of x is?

Solution

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Expression : 2cosAsinB = x

= $$cosAsinB + cosAsinB$$

Adding and subtracting $$(sinAcosB)$$

= $$(sinAcosB + cosAsinB) + (cosAsinB - sinAcosB)$$

= $$(sinAcosB + cosAsinB) - (sinAcosB - cosAsinB)$$

= $$sin(A+B) - sin(A-B)$$

=> Ans - (C)

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