If 2cosAsinB = x, then the value of x is?
Expression : 2cosAsinB = x
= $$cosAsinB + cosAsinB$$
Adding and subtracting $$(sinAcosB)$$
= $$(sinAcosB + cosAsinB) + (cosAsinB - sinAcosB)$$
= $$(sinAcosB + cosAsinB) - (sinAcosB - cosAsinB)$$
= $$sin(A+B) - sin(A-B)$$
=> Ans - (C)
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