A train is moving with a uniform speed. Train crosses a bridge of length 243 meters in 30 seconds and a bridge of length 343 meters in 36 seconds. Whatis the speed of the train?
Let the length of the train be T m.
Speed of the train = $$\dfrac{T+243}{30} = \dfrac{T+343}{36}$$
=> $$\dfrac{T+243}{5} = \dfrac{T+343}{6}$$
=> $$6T+1458 = 5T+1715$$
=> T = 257
Hence, Length of the train = 257 m
Therefore, Speed of the train $$= \dfrac{243+257}{30} = \dfrac{500}{30} = \dfrac{50}{3} m/sec = \dfrac{50}{3} \times \dfrac{18}{5} = 60 km/hr$$
Create a FREE account and get:
Detailed syllabus & Topic-wise Weightage
By proceeding you agree to create your account
Free CAT Syllabus PDF will be sent to your email address soon !!!
