Question 52

The greatest number that will divide 146, 248 and 611 leaving remainders 2,8 and 11 respectively is:

Solution

The greatest number that will divide 146, 248 and 611 leaving remainders 2,8 and 11 respectively

= H.C.F. of (146-2), (248-8), (611-11)

= H.C.F. (144,240,600) = 24

=> Ans - (C)

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