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If $$x = 100, y = 99$$ then find the value of $$\frac{x^2 + y^2 + xy}{x^3 - y^3}$$
$$(x^3-y^3)=(x-y)(x^2+xy+y^2)$$
So, required ratio= 1/(x-y)=1/(100-99)=1.
D is correct choice.
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