If the salary of A is 12% more than that of B, then by what percentage is the salary of B less than that of A? [Give your answer correct to 1 place of decimal.]
Let's assume the salary of B is 100y.
If the salary of A is 12% more than that of B.
the salary of A =Â 100y of (100+12)%
=Â $$100y\times\frac{112}{100}$$
 = 112y
the percentage is the salary of B less than that of A =Â $$\frac{\left(112y-100y\right)}{112y}\times100$$
= $$\frac{12y}{112y}\times100$$
=Â 10.7% (approx.)
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