If in  $$ \triangle ABC $$,D is a point on BC, such that BD : BC = 2 : 5, what is the ratio area$$(\triangle ABC) $$: area$$(\triangle ABD)$$? :
We Know that area of a triangle = (1/2) $$\times base \times height$$
The ratio area$$(\triangle ABC) $$: area$$(\triangle ABD)$$ = 5 : 2
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