A, B and C can do a work in 12, 15 and 20 days respectively. In how many days, working together they can complete the same work?
LCM of 12, 15, and 20 is 60 which can be assumed as the total work.
A, B and C can do a work in 12, 15 and 20 days respectively.
The efficiency of A =Â $$\frac{60}{12}$$ = 5 units/day
The efficiency of B =Â $$\frac{60}{15}$$ = 4 units/day
The efficiency of C =Â $$\frac{60}{20}$$ = 3 units/day
Time taken by all of them together to complete the same work =Â $$\frac{60}{5+4+3}$$
=Â $$\frac{60}{12}$$
= 5 days
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