Question 51

A dealer buys an article marked at ₹20000 with two successive discounts of 20% and 5%. He spends ₹1000 for its repair and sells it for ₹20000. What is his profit /loss percent (correct to two decimal places)?

Solution

Given, Marked Price = ₹20000

Price after 20% discount$$=\frac{80}{100}\times20000=₹16000$$

Price after 5% discount$$=\frac{95}{100}\times16000=₹15200$$

He spent ₹1000 for its repair

$$\therefore\ $$Cost price = 15200 + 1000 = ₹16200

Selling Price = ₹20000

Profit Percentage$$=\frac{Selling\ \Pr ice\ -Cost\ \Pr ice}{Cost\ \Pr ice}\times100=\frac{20000-16200}{16200}\times100=\frac{3800}{16200}\times100=23.46\%$$

Hence, the correct answer is Option C


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App