A and B together can do a piece of work in 12 days while A alone can do the same work in 30 days. B alone can do it in
Let total work to be done = 60 units
A can complete the work in 30 days
=> A's efficiency = $$\frac{60}{30}=2$$ units/day
Similarly, (A+B)'s 1 day's work = $$\frac{60}{12}=5$$ units/day
=> B's efficiency = $$5-2=3$$ units/day
$$\therefore$$ B alone can do the work in =Â $$\frac{60}{3}=20$$ days
=> Ans - (B)
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