A & B together finish a job in 24 days, while A, B & C together can finish the same job in 8 days. C alone will finish the job in

Question 51

Solution

Let total work to be done = 24 units

(A+B)'s 1 day's work = $$\frac{24}{24}=1$$ unit

(A+B+C)'s 1 day's work = $$\frac{24}{8}=3$$ units

=> C's 1 day's work alone = 3 - 1 = 2 units

$$\therefore$$ Time taken by C alone to complete the work = $$\frac{24}{2}=12$$ days

=> Ans - (A)

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