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The electricity bill of a certain establishment is partly fixed and partly varies with the number of units of electricity consumed. When in a certain month 540 units are consumed, the bill is ₹1800. In another month, 620 units are consumed, and the bill is ₹2040. In yet another month, 500 units are consumed. The bill for that month would be ..........
Let constant amount each month = Rs. $$A$$ and for $$x$$ units consumed it is Rs. $$B$$
=> For a month, total bill = $$A+Bx$$
According to ques, => $$A+540B=1800$$ ------------(i)
and $$A+620B=2040$$ ---------(ii)
Subtracting equation (i) from (ii), => $$80B=240$$
=> $$B=3$$
Substituting above value in equation (i), => $$A=1800-1620=180$$
$$\therefore$$ Bill for 500 units consumed = $$180+(500\times3)=180+1500=Rs.$$ $$1680$$
=> Ans - (A)
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