he has a point !

Hi vaish
Thanks for the update, the question has been updated:)

Hi Prithviraj Patil,
The minimum fare from A to J is if the route is AHJ. For all other routes fares will be high (solved in earlier questions)
for the route, AHJ fare is 2275
for the route, AFJ fare is 2850
If the prices include a margin of 15%, then the total cost for route AHJ will be lower compared to AFJ.
Therefore, we need to find the distance of the cheapest route (that is AHJ), 2275 km
I hope this helps!

Hi Atul,
The question states that the prices given in the table are after giving a 15% hike on the prices that the company incurs due to the travel. We need to find the path between A and J so that the price incurred by the flight company is minimal. We know that the price incurred by the company is 15% less than the price shown in the table, but it is a constant number for all the paths. So, we can conclude that the comparison between the prices in the table is enough for us to see the path of minimum cost for the company. We can see that the path A - H - J is the path with minimal cost to reach J from A, and the distance travelled in this path is 2350, which is the value that was asked in the question.
Hope this helps!

Hi Rohit,
The question asked is to calculate the distance travelled in the path where the cost incurred is minimum and not the cost incurred by the company. We can see that in the path of A - H - J, the distance covered is 1950 + 400 = 2350. 
Hope this helps!