A and B together can do a piece of work in 10 days. If A can do the work in 15 days,find in how many days that B alone can do the same work. Given below are the steps involved in solving the above problem. Arrange them in sequential order.
A) One day's work of B is $$\frac{1}{10} - \frac{1}{15}$$
B) One day's work of A and B is $$Â \frac{1}{10}$$ and one day's work of A is $$ \frac{1}{15} $$
C) B alone can do the work in 30 daysÂ
D) One day's work of B is $$Â \frac{1}{30} $$
One day's work of A and B = $$ \frac{1}{10}$$
One day's work of A = $$ \frac{1}{15} $$
One day's work of B = $$\frac{1}{10} - \frac{1}{15}$$ =Â $$ \frac{1}{30} $$
B alone can do the work in 30 days.
The correct order would be BADC.
So , the answer would be option a)BADC.
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