In $$\triangle PQR$$, $$I$$ is the incentre of the triangle. If $$\angle QIR = 107^\circ$$, then what is the measure of $$\angle P$$?
$$\angle QIR = 90 \degree + \angle P/2$$
107 =Â 90 $$\degree + \angle P/2$$
$$ \angle P/2 = 17\degree$$
$$ \angle P = 34\degree$$
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