Question 48

In $$\triangle PQR$$, $$I$$ is the incentre of the triangle. If $$\angle QIR = 107^\circ$$, then what is the measure of $$\angle P$$?

Solution

$$\angle QIR = 90 \degree + \angle P/2$$
107 = 90 $$\degree + \angle P/2$$
$$ \angle P/2 = 17\degree$$
$$ \angle P = 34\degree$$


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