Question 46

Which two signs should be interchanged to make the given equation correct?
$$286 \div 13 \times 2 + 50 - 6 = 0$$

The given equality is $$286 \div 13 \times 2 + 50 - 6 = 0$$. We have to choose one pair of operators and interchange them so that the equality holds true.

Try interchanging the operators suggested in each option one by one.

Case A: Interchange $$+$$ and $$-$$.
The new expression becomes $$286 \div 13 \times 2 - 50 + 6$$.

Solve using the normal BODMAS/PEMDAS order:

Step 1: Divide - $$286 \div 13 = 22$$.

Step 2: Multiply - $$22 \times 2 = 44$$.

Step 3: Add/Subtract from left to right - $$44 - 50 + 6$$.
  • $$44 - 50 = -6$$.
  • $$-6 + 6 = 0$$.

The left-hand side equals $$0$$, which satisfies the equation. Hence interchanging $$+$$ and $$-$$ makes the equation correct.

We need not test the remaining options because exactly one option must work in a single-correct JEE Main question, and we have already found it.

Option A which is: $$+$$ and $$-$$

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