The value of $$\left\{\left(6 + 4\right) + \left(12 \div 4 \times 2\right)\right\} + 1 \frac{1}{3} \times 9 \div 3 + 1\frac{2}{3}$$ is:

A

$$\frac{65}{3}$$

B

$$\frac{23}{3}$$

C

$$\frac{55}{3}$$

D

$$\frac{17}{3}$$