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Question 45
The radius of base of a solid cylinder is 7 cm and its height is 21 cm. It is melted and converted into small bullets. Each bullet is of same size. Each bullet consisted of two parts viz. a cylinder and a hemisphere on one of its base. The total height of bullet is 3.5 cm and radius of base is 2.1 cm. Approximately how many complete bullets can be obtained?
Solution
The bullet will look like :
Now height of cylinder will be 3.5-2.1 =1.4
Now Volume of a cylinder = n(Volume of a bullet )
we get
$$\pi\ \times\ 7^2\times\ 21=n\left(\frac{2}{3}\pi\ \times\ \left(2.1\right)^3\right)\ +\ \pi\ \times\ 1.4\times\ 2.1\times\ 2.1$$
solving we get
n =83
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