Question 45

The chord AB of a circle of centre O subtends an angle θ with the tangent at A to the circle. Then measure of∠ABO is

Solution

Given : $$\angle$$ BAC = $$\theta$$

To find : $$\angle$$ ABO = ?

Solution : AC is the tangent of the circle, => $$\angle$$ OAC = $$90^\circ$$

=> $$\angle$$ OAB = $$90^\circ-\theta$$

Also, OA = OB = radii of circle

=> $$\angle$$ OBA = $$\angle$$ OAB = $$90^\circ-\theta$$

=> Ans - (B)

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