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Question 45
The chord AB of a circle of centre O subtends an angle θ with the tangent at A to the circle. Then measure of∠ABO is
Solution
Given : $$\angle$$ BAC = $$\theta$$
To find : $$\angle$$ ABO = ?
Solution : AC is the tangent of the circle, => $$\angle$$ OAC = $$90^\circ$$
=> $$\angle$$ OAB = $$90^\circ-\theta$$
Also, OA = OB = radii of circle
=> $$\angle$$ OBA = $$\angle$$ OAB = $$90^\circ-\theta$$
=> Ans - (B)
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