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Question 44
What is the simplified value of $$[\frac{(tan^2 θ - sin^2 θ)}{(tan^2 θsin^2 θ)}]$$ ?
Solution
$$[\frac{(tan^2 θ - sin^2 θ)}{(tan^2 θsin^2 θ)}]$$
$$\left(\frac{\sin^2\theta\left(\frac{1}{\cos^2\theta}-1\right)}{\tan^2\theta\sin^2\theta}\ =\ \frac{\left(1-\cos^2\theta\right)}{\tan^2\theta\cos^2\theta}\right)$$
$$\frac{\sin^2\theta}{\sin^2\theta}\ =\ 1$$
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