Question 44

There are three boxes of three different colours- Green, Blue and Red, and 6 toys of which 2 are of Green colour, 2 are of Blue colour and 2 are of Red colour. The toys are packed in the three boxes such that each box has 2 toys of different colours in it and also the colour of the box is different from the colour of the toys packed in it. Now, 10 chocolates are kept in these boxes in such a way that the Green box has the maximum possible chocolates in it whereas, the Red box has the least possible chocolates in it. Each box should have at least one chocolate and no two boxes have the same number of chocolates.
Which of the following is true?

Solution

Given that there are 3 boxes of green blue red colours

According to the given condition,that the box color toy is not present in respective box,

green box has blue and red toys

Blue box has Green and  red toys

Red box has Green and blue toy

There are 10 chocolates The least number of chocolates are in red box. Given that atleast one chocolate in red box

and maximum possible number of chocolates in Green box

that is 7 is the maximum number of chocolates because 2 chocolates are kept in blue box.

Therefore, option D is correct that is the box which has green and red toys has 2 chocolates. such box is Blue box which has 2 chocolates in it.


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