The equation of the plane through the line $$ \frac {x - 1}{3} = \frac {y - 4}{2} = \frac {z - 4}{-2} $$ and parallel to the line $$ \frac {x + 1}{2} = \frac {y - 1}{-4} = \frac {z + 2}{1} $$ is

A

$$3x + 2y - 2z = 101$$

B

$$2x - 4y + z = 98$$

C

$$6x + 7y + 16z = 98$$

D

$$6x - 8y - 2z = 101$$