Pipes P and Q can fill a tank in 20 and 16 hours respectively. Pipe Q alone was opened for $$\frac{1}{4}$$ of time and later P also was opened. In how many hours was the tank filled?
Let the required time be x hours.
then Pipes, P & Q :
⇒ x/16+3x/80 = 1
⇒ 8x/80= 1
=>x=10 hours.
B is correct choice.
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