Question 44

The sum of the digits of a two-digit number is 9 less than the number. Which of the following digits is at ten's place of the number ?

Solution

Let say, the number is 'ab'.

So, $$ab=10a+b.$$

According to question,

$$a+b=10a+b-9.$$

or, $$a=1.$$

So, digit in ten's place is 1.

D is correct choice.

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