In the figure (not drawn to scale) given below, if AD = DC = BC and ∠BCE = 96°,then ∠DBC is
Let CAD be x
so ACD = x
Now we get CDB = 2x
So CBD = 2x
Therefore DCB = 180-4x
Now 96+180-4x+x = 180
we get x = 32
So DBC = 2x = 64
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