Question 43
ΔABC is right angled at B. BD is an altitude. AD = 9 cm and DC = 16 cm. What is the value of BD (in cm)?
Solution
Given : AD = 9 cm and DC = 16 cm
To find : BD = ?
Solution : In $$\triangle$$ ABC
=> $$(BD)^2=(AD)\times(DC)$$
=> $$(BD)^2=9\times16=144$$
=> $$BD=\sqrt{144}=12$$ cm
=> Ans - (D)
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