Question 43

ΔABC is right angled at B. BD is an altitude. AD = 9 cm and DC = 16 cm. What is the value of BD (in cm)?

Solution

Given : AD = 9 cm and DC = 16 cm

To find : BD = ?

Solution : In $$\triangle$$ ABC

=> $$(BD)^2=(AD)\times(DC)$$

=> $$(BD)^2=9\times16=144$$

=> $$BD=\sqrt{144}=12$$ cm

=> Ans - (D)

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