Three of the following four letter-clusters are alike in a certain way and one is different.
Pick the odd one out.

Write the alphabetical positions: $$A=1,\;B=2,\;\dots ,\;Z=26$$.

Check the jump from the 1st to the 2nd letter and from the 3rd to the 4th letter in each cluster, always moving forward through the alphabet and allowing wrap-around after $$Z$$ (cyclic counting).

$$X(24)\rightarrow Z(26) : +2$$
$$W(23)\rightarrow B(2) : +5$$ (because $$W\,X\,Y\,Z\,A\,B$$ counts 5 steps forward)

$$R(18)\rightarrow T(20) : +2$$
$$Q(17)\rightarrow V(22) : +5$$

$$N(14)\rightarrow P(16) : +2$$
$$M(13)\rightarrow R(18) : +5$$

$$V(22)\rightarrow X(24) : +2$$
$$T(20)\rightarrow Z(26) : +6$$

Thus, in Options A, B and D the pattern “$$+2$$ then $$+5$$” holds, whereas Option C breaks the pattern (it shows “$$+2$$ then $$+6$$”).

Hence the odd one out is:
Option C which is: VXTZ