Question 42

In a basket there are seven different fruits M, N, O, P, Q, R and S, each having a different weight. P is the heaviest. The weight of S is more than Q but less than O. The weight of M is the third lowest. R has the least weight. The weight of N is less than Q. How many fruits have more weight than S?

Solution

P is the heaviest.

P>>>>>>

The weight of M is the third lowest.

P>>>>M>>

R has the least weight.

P>>>>M>>R Eq.(i)

The weight of S is more than Q but less than O. The weight of N is less than Q.

O>S>Q>N Eq.(ii)

Merge Eq.(i) and Eq.(ii).

P>O>S>Q>M>N>R

According to the above arrangement, Two fruits have more weight than S.

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