Consider the above reaction, the major product 'P' is:

Option A represents only the intermediate tertiary alcohol formed after Grignard addition and ignores the subsequent reaction with $$HCl$$.

Option B incorrectly assumes hydrogenation of the double bond, which cannot occur with the given reagents.

Option C represents the correct final product formed after electrophilic addition of $$HCl$$ across the double bond according to Markovnikov’s rule.

The proton adds to the terminal carbon, while $$Cl^-$$ attaches to the more substituted carbon.

Option D represents the anti-Markovnikov product, which is not formed because $$HCl$$ normally follows Markovnikov addition in the absence of peroxide conditions.

Therefore, Option C is the major product.