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To determine which species responds to an external magnetic field, we identify the complex containing unpaired electrons.
Complexes with unpaired electrons are:
$$\mathrm{Paramagnetic}$$
while complexes with all electrons paired are:
$$\mathrm{Diamagnetic}$$
(A)
$$\mathrm{[Fe(H_2O)_6]^{3+}}$$
Oxidation state of iron:
$$\mathrm{Fe^{3+}}$$
Electronic configuration:
$$\mathrm{3d^5}$$
$$\mathrm{H_2O}$$ is a weak field ligand and does not cause electron pairing.
Thus, the complex contains:
$$\mathrm{5\ unpaired\ electrons}$$
Hence:
$$\mathrm{[Fe(H_2O)_6]^{3+}}$$
is strongly paramagnetic.
(B)
$$\mathrm{[Ni(CN)_4]^{2-}}$$
Oxidation state of nickel:
$$\mathrm{Ni^{2+}}$$
Electronic configuration:
$$\mathrm{3d^8}$$
$$\mathrm{CN^-}$$ is a strong field ligand and causes complete pairing of electrons.
Thus:
$$\mathrm{0\ unpaired\ electrons}$$
Hence, the complex is diamagnetic.
(C)
$$\mathrm{[Co(CN)_6]^{3-}}$$
Oxidation state of cobalt:
$$\mathrm{Co^{3+}}$$
Electronic configuration:
$$\mathrm{3d^6}$$
$$\mathrm{CN^-}$$ is a strong field ligand.
All electrons pair in the lower-energy orbitals.
Thus:
$$\mathrm{0\ unpaired\ electrons}$$
Hence, the complex is diamagnetic.
(D)
$$\mathrm{[Ni(CO)_4]}$$
Oxidation state of nickel:
$$\mathrm{Ni^0}$$
Electronic configuration:
$$\mathrm{3d^{10}}$$
$$\mathrm{CO}$$ is a very strong field ligand and causes complete pairing.
Thus:
$$\mathrm{0\ unpaired\ electrons}$$
Hence, the complex is diamagnetic.
Therefore, the only paramagnetic complex is:
$$\boxed{\mathrm{[Fe(H_2O)_6]^{3+}}}$$
Correct option:
$$\boxed{\mathrm{A}}$$
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