CAT 2001 Question Paper Question 42

Question 42

Based on the figure below, what is the value of x, if y = 10?

Solution

We will solve this question by taking the options.

Suppose x = 11

x+4 = 15, x-3 = 8

Hyptenuse = $$\sqrt{225+64} = 17$$

17-11 = 6

$$6^2+(x-3)^2 = y^2$$

x-3 = 8

y = 10 which is similar to what is given in the question.

Hence x = 11



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Comments
Kshitij Bajpai

1 year, 8 months ago

kucbhi?

cracku

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