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Question 41
A circle touches the side BC of $$\triangle$$ABC at D and AB and AC are produced to E and F, respectively. If AB = 10 em, AC = 8.6 cm and BC = 6.4 cm, then BE =?
Solution
Perimeter of $$\triangle ABC$$ = 10 +Â 8.6 + 6.4 = 25 cm
AE + EF = 25 cm
AE = EF = 25/2 = 12.5 cm
BE = AE - AB = 12.5 - 10 = 2.5 cm
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