Question 40

The internal bisectors of ∠Q and ∠R of triangle PQR meet at O. If ∠P = 70°, then what is the measure of ∠QOR (in degrees)?

Solution

Given : O is the incentre of $$\triangle$$ PQR and $$\angle$$ P = 70°

To find : $$\angle$$ QOR = $$\theta$$ = ?

Incentre of a triangle = $$90^\circ+\frac{1}{2} \times $$ (Angle opposite to it)

=> $$\theta=90^\circ+\frac{70^\circ}{2}$$

=> $$\theta=90^\circ+35^\circ$$

=> $$\theta=125^\circ$$

=> Ans - (C)

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