Question 40
The internal bisectors of ∠Q and ∠R of triangle PQR meet at O. If ∠P = 70°, then what is the measure of ∠QOR (in degrees)?
Solution
Given : O is the incentre of $$\triangle$$ PQR and $$\angle$$ P = 70°
To find : $$\angle$$ QOR = $$\theta$$ = ?
Incentre of a triangle = $$90^\circ+\frac{1}{2} \times $$ (Angle opposite to it)
=> $$\theta=90^\circ+\frac{70^\circ}{2}$$
=> $$\theta=90^\circ+35^\circ$$
=> $$\theta=125^\circ$$
=> Ans - (C)
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