Question 40

If 8&4 = 64, 5&8 = 80 and 8&1 = 16, then find the value of 9&9 = ?

Solution

Given : 8&4 = 64, 5&8 = 80 and 8&1 = 16

If we replace '&' with 'x' and also multiply the final result with '2', then we will get the desired result.

Eg :- $$2\times(8\times4)=64$$

and $$2\times(5\times8)=80$$ and $$2\times(8\times1)=16$$

Similarly, $$2\times(9\times9)=162$$

=> Ans - (C)

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