Question 40

If 5@1=60; 12@8=200; 16@2=180; then what is the value of 16@10=?

Solution

The pattern followed is for $$a$$@$$b$$ = $$(a+b)\times10$$

Eg = 5@1 = $$(5+1)\times10=6\times10=60$$

and 12@8 = $$(12+8)\times10=20\times10=200$$

and 16@2 = $$(16+2)\times10=18\times10=180$$

Similarly, 16@10 = $$(16+10)\times10=26\times10=260$$

=> Ans - (D)

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