Given : 3!5 = 30, 6!1 = 12 and 5!8 = 80
If we replace '!' with 'x' and also multiply the final result with '2', then we will get the desired result.
Eg :- $$2(3\times5)=30$$
and $$2(6\times1)=12$$ and $$2(5\times8)=80$$
Similarly, $$2(2\times2)=8$$
=> Ans - (C)
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