SSC CHSL 23 March 2018 Evening Shift Question 4

Question 4

The product of two even consecutive numbers is 168. Find the sum of numbers.

Solution

Let the two consecutive even numbers be $$x,(x+2)$$

Product = $$x(x+2)=168$$

=> $$x^2+2x-168=0$$

=> $$x^2+14x-12x-168=0$$

=> $$x(x+14)-12(x+14)=0$$

=> $$(x+14)(x-12)=0$$

=> $$x=-14, 12$$

$$\because$$ $$x$$ cannot be negative, => $$x=12$$

$$\therefore$$ Sum of numbers = $$x+(x+2)=2x+2$$

= $$2(12)+2=24+2=26$$

=> Ans - (D)



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