The product of two even consecutive numbers is 168. Find the sum of numbers.
Let the two consecutive even numbers be $$x,(x+2)$$
Product = $$x(x+2)=168$$
=> $$x^2+2x-168=0$$
=> $$x^2+14x-12x-168=0$$
=> $$x(x+14)-12(x+14)=0$$
=> $$(x+14)(x-12)=0$$
=> $$x=-14, 12$$
$$\because$$ $$x$$ cannot be negative, => $$x=12$$
$$\therefore$$ Sum of numbers = $$x+(x+2)=2x+2$$
=Â $$2(12)+2=24+2=26$$
=> Ans - (D)
Create a FREE account and get:
