Solution
Given : $$p$$ & $$q = p^2 + 4pq - q^2$$
To find : $$(3$$&$$6) + (4$$&$$5)$$
= $$(3^2+4\times3\times6-6^2)+(4^2+4\times4\times5-5^2)$$
= $$(9+72-36)+(16+80-25)$$
= $$45+71=116$$
=> Ans - (C)
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