Question 4

If $$7^{m+1}=2401$$, then find the value of $$2^{2m+2}$$

Solution

Given : $$7^{m+1}=2401$$

=> $$7^{m+1}=7^4$$

=> $$m+1=4$$

=> $$m=4-1=3$$

$$\therefore$$ $$2^{2m+2}=2^{2\times3+2}$$

= $$2^8=256$$

=> Ans - (B)

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