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If $$7^{m+1}=2401$$, then find the value of $$2^{2m+2}$$
Given : $$7^{m+1}=2401$$
=> $$7^{m+1}=7^4$$
=> $$m+1=4$$
=> $$m=4-1=3$$
$$\therefore$$ $$2^{2m+2}=2^{2\times3+2}$$
= $$2^8=256$$
=> Ans - (B)
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