Solution
Given : $$x-\frac{1}{x}=10$$
Squaring both sides, we get :
=> $$(x-\frac{1}{x})^2=(10)^2$$
=> $$x^2+\frac{1}{x^2}-2(x)(\frac{1}{x})=100$$
=> $$x^2+\frac{1}{x^2}=100+2$$
=> $$\frac{x^4+1}{x^2}=102$$
=> Ans - (C)
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