A metal bar of length $$\ell$$ moves with a velocity $$v$$ parallel to an infinitely long straight wire carrying a current $$I$$ as shown in the figure. If the nearest end of the perpendicular bar always remains at a distance $$2\ell$$ from the current carrying wire, the potential difference in volt between two ends of the moving bar is

A

$$\frac{\mu_0Iv}{2\pi}$$

B

$$\frac{\mu_0Iv}{6\pi}$$

C

$$\frac{\mu_0Iv}{2\pi}\ln 2$$

D

$$\frac{\mu_0Iv}{2\pi}\ln 1.5$$