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Solution
$$\log_{2}{\log_{7}{(x^2 - x+37)}}$$ = 1
$$\log_{7}{(x^2 - x+37)}$$ = $$2$$
$$(x^2 - x+37)$$ = $$7^{2}$$
Given eq. can be reduced to $$x^2 - x + 37 = 49$$
So x can be either -3 or 4.
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